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Binomial Theorem – Applications, Coefficient Problems, Greatest Term

Maths Higher · Grade 11 · Week 20 · 25 questions

This Grade 11 mathematics chapter on Binomial Theorem introduces Applications, Coefficient Problems, and Greatest Term. The logical tools introduced here power later work in calculus, algebra, and vectors.

What you'll practise

  • Identify Applications
  • Solve Coefficient Problems
  • Evaluate Greatest Term
  • Apply binomial theorem concepts to NCERT exercise and exemplar problems
All 25 questions in this Binomial Theorem – Applications, Coefficient Problems, Greatest Term quiz

Grade 11 Maths HigherBinomial Theorem – Applications, Coefficient Problems, Greatest Term: 25 practice questions with instant scoring and explanations.

  1. The sum 1 + 5 + 10 + 10 + 5 + 1 is equal to:
  2. If the greatest term in the expansion of (1 + x)ⁿ has coefficient nCr, then the greatest term is:
  3. The greatest coefficient in the expansion of (2 + 3)⁷ is:
  4. The sum of the coefficients in the expansion of (x - y)ⁿ is:
  5. Using the binomial theorem, (1.02)⁵ ≈
  6. The value of (99)⁴ using binomial theorem is:
  7. In the expansion of (1 + x)ⁿ, the ratio of the (r+1)th term to the rth term is:
  8. The coefficient of x in (1 + x)ⁿ is:
  9. If Tᵣ is the greatest term in the expansion of (1 + x)ⁿ, then Tᵣ₊₁/Tᵣ ≤ 1 gives:
  10. The greatest term in the expansion of (3 + 2x)¹⁰ when x = 1 occurs at:
  11. (1 + 2 + 2² + 2³ + ... + 2ⁿ) can be obtained from binomial expansion by:
  12. The sum ⁿC₀ + 2·ⁿC₁ + 3·ⁿC₂ + ... + (n+1)·ⁿCₙ equals:
  13. The number of integral terms in the expansion of (∛2 + ∜3)²⁴ is:
  14. If (1 + x)ⁿ = 1 + 4x + 6x² + 4x³ + x⁴, then n =
  15. The approximate value of ∜(16.81) using binomial expansion is:
  16. In the expansion of (x + y)ⁿ, if a term is independent of both x and y, it is:
  17. The sum ⁿC₀ - ⁿC₁ + ⁿC₂ - ⁿC₃ + ... + (-1)ⁿ·ⁿCₙ equals:
  18. Using binomial theorem, ∛(1000 + 1) ≈
  19. The greatest coefficient in the expansion of (x + y)⁷ is:
  20. If in the expansion of (x + 1/(x^α))⁶, the term independent of x has coefficient 20, then α =
  21. The value of ⁶C₀ + ⁶C₃ + ⁶C₆ + ... is:
  22. In the expansion of (x - 1/x)⁶, the constant term is:
  23. The ratio of the greatest term to the preceding term in (1 + 1/10)¹⁰ is:
  24. Using binomial approximation, (1.01)⁵ ≈
  25. The middle term in (x + y)⁶ is T₄ with coefficient:
Question 1 of 250 correct so far

The sum 1 + 5 + 10 + 10 + 5 + 1 is equal to: