
Geometric Progressions β nth Term, Sum, Infinite GP
Maths Higher Β· Grade 11 Β· Week 22 Β· 25 questions
This Grade 11 mathematics chapter on Geometric Progressions introduces nth Term, Sum, and Infinite GP. Speed and accuracy here translate directly into better JEE-level problem solving.
What you'll practise
- Prove nth Term
- Solve Sum
- Evaluate Infinite GP
- Apply geometric progressions concepts to NCERT exercise and exemplar problems
All 25 questions in this Geometric Progressions β nth Term, Sum, Infinite GP quiz
Grade 11 Maths Higher β Geometric Progressions β nth Term, Sum, Infinite GP: 25 practice questions with instant scoring and explanations.
- A geometric progression (GP) is a sequence where:
- The nth term of a GP with first term a and common ratio r is:
- For the GP 2, 6, 18, 54, ..., the common ratio is:
- The sum of first n terms of a GP with a β 0 and r β 1 is:
- The sum of an infinite GP with |r| < 1 is:
- For an infinite GP to have a finite sum, the condition is:
- The 5th term of the GP 1, 2, 4, 8, ... is:
- The sum of first 6 terms of the GP 2, 4, 8, ... is:
- The sum of the infinite GP 1 + 1/2 + 1/4 + 1/8 + ... is:
- If the first term of a GP is 3 and the 4th term is 81, the common ratio is:
- If a, ar, arΒ² are three consecutive terms, then the third term in terms of first two is:
- The sum 1 + 2 + 4 + ... + 512 is:
- In a GP, if a = 1 and r = 2, then the sum of the first 10 terms is:
- The sum 1 - 1/2 + 1/4 - 1/8 + ... is:
- For the infinite GP 0.3 + 0.03 + 0.003 + ..., the sum is:
- The geometric mean of two numbers a and b is:
- If p, q, r are in GP, then:
- The sum of the GP 1/2 + 1/4 + 1/8 + ... + 1/128 is:
- If the first term is a and the sum to infinity is 4a, then the common ratio is:
- In a GP, if the 3rd term is 4 and the 6th term is 32, the first term is:
- The repeating decimal 0.777... equals:
- For which value of r does the sum of infinite GP become undefined?
- The sum of the GP 8, 4, 2, 1, ... to infinity is:
- If a GP has 5 terms with first term 2 and last term 162, the sum is:
- The sum 2 + 6 + 18 + ... + 2Β·3βΆ equals:
Question 1 of 250 correct so far