
Applications - Rate of Change, Tangents & Normals
Maths Higher · Grade 12 · Week 16 · 25 questions
This Grade 12 mathematics chapter on Applications is high-yield for CBSE + JEE, exploring Rate of Change and Tangents & Normals. This chapter regularly carries 8-13 marks in CBSE Grade 12 — theorems + application problems are standard.
What you'll practise
- Evaluate Rate of Change
- Solve Tangents & Normals
- Solve CBSE board-pattern problems from applications including NCERT exemplar-level questions
All 25 questions in this Applications - Rate of Change, Tangents & Normals quiz
Grade 12 Maths Higher — Applications - Rate of Change, Tangents & Normals: 25 practice questions with instant scoring and explanations.
- The rate of change of a quantity with respect to time is represented by:
- For a curve y = f(x), the slope of tangent at (a, f(a)) is:
- The equation of tangent to y = f(x) at (a, f(a)) is:
- The slope of normal to a curve at a point is:
- If tangent slope is m, then normal slope is:
- For y = x² at (2, 4), the tangent slope is:
- The normal to y = √x at (1, 1) has equation:
- If water flows out of tank at rate 5 L/min, then dV/dt =
- For a spherical balloon with radius r, the rate of volume change dV/dr =
- Related rates problems use:
- A ladder against wall: if dx/dt is horizontal speed, the dy/dt is:
- For a growing circle, if dr/dt = 2 cm/s, then dA/dt at r = 5 =
- The normal vector direction is:
- For y = sin(x) at x = π/2, the tangent line is:
- The angle between two curves is the angle between their:
- If f'(x) = 0 at x = a, the tangent at a is:
- The equation of normal to y = e^x at (0, 1) is:
- For population growth P(t), the rate dP/dt represents:
- A particle's velocity v = dx/dt and acceleration a = d²x/dt² = dv/dt =
- For velocity v = t² - 3t + 2, acceleration a = dv/dt =
- Orthogonal trajectories are curves that:
- Finding orthogonal trajectories uses:
- The angle of inclination θ of tangent line relates to slope m by:
- If two curves are perpendicular at intersection, m₁·m₂ =
- Slope of tangent to y = x² at x = 2:
Question 1 of 250 correct so far